What is this callback in nodesayncqueue and why is there only 5 lines of output here?

  node.js, question

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Of course, because your concurrency is 5, but not in your queuefork callback, so the concurrency is 5, no end will not be adjusted.

var async = require('async');
 var q = async.queue(function(data, callback) {
 console.log(data.name);
 // fork callback
 callback();
 }, 5);
 for(var i = 0;   i < 10;  Add I)
 q.push({ name: 0 })
 bracket